SOLUTION: A panel of 6 members is to be formed from 5 doctors and 10 nurses to include each profession. Find, correct to two decimal places, the probability of selecting the members to inclu

Question 1196248: A panel of 6 members is to be formed from 5 doctors and 10 nurses to include each profession. Find, correct to two decimal places, the probability of selecting the members to include: (a) equal doctors and nurses; (b) at most two nurses; (c) more doctors than nurses.
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.

In my post, I will solve only one part, namely part (a).

(a)  "equal doctors and nurses" means "3 doctors and 3 nurses".

     The answer is  P(3 of 5; 3 of 10) =  =  = 0.23976    (rounded).    ANSWER

Solved.

------------

I do not like to solve many problems in one post, because I think that it is BAD WAY to teach.

By the way, the rules of this forum require ONE problem per post. See the page

https://www.algebra.com/tutors/students/ask.mpl?action=ask_question&topic=Equations&return_url=http://www.algebra.com/algebra/homework/equations/

from which you post your problems.

RELATED QUESTIONS
A panel of 6 members is to be formed from 5 doctors and 10nurses to include each... (answered by greenestamps)

A panel of 6 members is to be formed from 5 doctors and 10nurses to include each... (answered by mananth,ikleyn)

A committee of 5 people is to be formed from 10 doctors and 8 dentists. Find the... (answered by stanbon)

a commitee is formed by randomly selecting from eight nurses and two doctors. what is the (answered by jsmallt9)

In hospital, there are 12 nurses and 4 doctors ,then: if a committee of 4 nurses and 2... (answered by jorel1380)

In hospital, there are 12 nurses and 4 doctors,then: if a committee of 4 nurses and 2... (answered by math_helper)

A party of 6 is to be formed from 10 men and 7 women so as to include 3 men and 3 women.... (answered by Edwin McCravy)

There are 9 nurses and 6 doctors working in a hospital ward. How many ways could they... (answered by Edwin McCravy)

Please help me solve this problem. A committee of 4 people is to be form from 6 doctors... (answered by oscargut)