SOLUTION: In how many ways can the first, second and third place winners be selected from 8
contestants?
Algebra.Com
Question 1192636: In how many ways can the first, second and third place winners be selected from 8
contestants?
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52832) (Show Source): You can put this solution on YOUR website!
.
In 8*7*6 = 336 different ways.
It is the product of three consecutive integers in descending order starting from 8.
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See the lesson
- Special type permutations problems
in this site. Find there many solved similar problems.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
In how many ways can the first, second and third place winners be selected from 8
contestants?
=====================
Why would winners be "selected?"
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