SOLUTION: Given the digits 1,2,4,6,8 and 9, how many four - digit numbers can be formed if repetition is not allowed.

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Question 1192086: Given the digits 1,2,4,6,8 and 9, how many four - digit numbers can be formed if repetition is not allowed.

Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
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Any of 6 given digits in the left-most position, giving 6 options;


any of remaining 5 digits in the next position, giving 5 options;


any of remaining 4 digits in the next position, giving 4 options;


any of remaining 3 digits in the last position, giving 3 options.


The ANSWER is the product of the number of options in each position


    6*5*4*3 = 360 different numbers.

Solved.

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See the lesson
    - Special type permutations problems

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Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


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Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

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