First (left-most) digit can be any from 1 to 9. Next (tens) digit can be any from 0 to 9. Therefore, there are 9*10 = 90 such three-digit numbers.
Consider the set of all such 3-digit numbers. Cut the last digit: you will get the set of all 2-digit numbers. The cardinality of this set of 2-digit numbers is 90 - - - it gives the answer.