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How many ways can we select three books each from a different subject
from a set of six distinct history books, nine distinct classics books,
seven distinct law books, and four distinct education books?
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We have the sets
- H (history, 6 books)
- C (classic, 9 books)
- L (law, 7 books)
- E (educational, 4 books).
We can select 3 different subject books from the set H U C U L by 6*9*7 = 378 ways.
We can select 3 different subject books from the set H U C U E by 6*9*4 = 216 ways.
We can select 3 different subject books from the set H U L U E by 6*7*4 = 168 ways.
We can select 3 different subject books from the set C U L U E by 9*7*7 = 252 ways.
Doing this way, we counted all possible combinations of 3 different subject books.
So, the answer to the problem's question is the sum 378 + 216 + 168 + 252 = 1014 different ways.
Solved and carefully explained.