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A class contains 9 men and 3 women:
(a) How many committee of 4 student can be selected? Ans=495
(b) How many of them contain at least 2 women?
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(a) = 495. ANSWER
(b) + = 3*36 + 1*9 = 108 + 9 = 117. ANSWER
Solved.
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In the post by @greenestamps, the formula for part (b) has an error.
It is why I came to correct it.
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This problem is on COMBINATIONS.
It combines your knowledge on combinations and the Fundamental counting principle.
To learn the subject, see these introductory lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- Fundamental counting principle problems
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.