SOLUTION: In how many ways can a president,a secretary and a treasurer be chosen in a group with 9 members assuming that no one can occupy 2 or more positions?

Question 1178265: In how many ways can a president,a secretary and a treasurer be chosen in a group with 9 members assuming that no one can occupy 2 or
more positions?
Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.

In 9*8*7 = 448 ways.             ANSWER

There are 9P3 such permutations.

Solved.

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This problem is on   PERMUTATIONS.

See the lesson
    - Special type permutations problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.

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