.
There are 11 symbols/letters in all.
Of them, "I" has the multiplicity 4;
"S" has the multiplicity 4;
"P" has multiplicity 2.
Therefore, the number of all possible distinguishable arrangements of the letters is = = 34650.
The factorials in the denominator account for permutations of repeating letters.
Solved, answered and explained.
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- Arranging elements of sets containing indistinguishable elements
in this site.
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- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
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Free of charge online textbook in ALGEBRA-II
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