SOLUTION: Vannessa plans to arrange A,B,C,D,E,F,G and H in a row on the wall. Find the number of Permutations for the following: A and B must be places next to each other

Question 1175182: Vannessa plans to arrange A,B,C,D,E,F,G and H in a row on the wall. Find the number of Permutations for the following:
A and B must be places next to each other
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi A and B must be places next to each other: Consider them as one unit Find the number of Permutations: 7!(2) (AB 0r BA)) Wish You the Best in your Studies.

Answer by ikleyn(52805)   (Show Source): You can put this solution on YOUR website!
.

For the rest of 6 letters, C, D, E, F, G and H, there are 6! = 720 possible permutations.

For each of these 720 permutations, we have 7 positions to place the blocked AB or BA.

THEREFORE, the full number of possible arrangements, satisfying the posed conditions, is

            6!*2*7 = 2*7! = 10080.             ANSWER

Solved.

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