.
How many ways are there for 5 men and seven women to stand in a line so that three women
stand next to each other
~~~~~~~~~~~~~
From the remote point of view, you consider these 3 women as one clued object.
So the total number of object to permute, from this point of view is 5 + 7 - 2 = 10.
For 10 objects, you have 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 permutations.
Now, from the close point of view, there are 3! = 3*2*1 = 6 possible permutations inside this group of the 3 women.
It gives the total 6*3628800 = 10886400 possible permutationns. ANSWER
Solved.