.
In my previous post (see the link at the end of this post), I explained that there are 8! = 40320 permutations for 8 items.
I also explained that there are 2*7! = 2 * 5040 = 10080 permutations, where the most difficult and easiest questions
go next to each other (= are neighbors).
Hence, the number of those permutations, where these questions ARE NOT neighbors is the difference
40320 - 10080 = 30240. ANSWER
Solved.
It is the link to the referred post
https://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.1173252.html
https://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.1173252.html
==============
If you want to see many similar solved problems on PERMUTATIONS, see my lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Simple and simplest problems on permutations
- Special type permutations problems
- Problems on Permutations with restrictions
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.