SOLUTION: A committee of eight people is to be chosen from 10 males and 11 females. How many ways are there to choose a committee that would consist of an equal number of males and females?

Question 1170029: A committee of eight people is to be chosen from 10 males and 11 females. How many ways are there to choose a committee that would consist of an equal number of males and females?
Answer by smaira(1) (Show Source): You can put this solution on YOUR website!
A committee of 8 people is to be chosen.
No. of males = females
Thus, males= females= 4
No. of ways = 10C4 x 11C4
= (10 x 9 x 8 x 7)/(4 x 3 x 2 x 1) x (11 x 10 x 9 x 8)/(4 x 3 x 2 x 1)
= 210 x 330
= 69300
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