SOLUTION: Find the number of ways of permutation the word hell such that the 2ls will always be together

Algebra.Com
Question 1160371: Find the number of ways of permutation the word hell such that the 2ls will always be together

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
if you want to have the L's be together, then treat them as one.
your permutation becomes 3! rather than 4!.
3! = 3 * 2 * 1 = 6 ways this can happen.
the ways are:
HELL
EHLL
HLLE
ELLH
LLEH
LLHE
since this is a permutation, and not a combination, each set is considered different, even though each may contain the same letters, since order is important in a permutation, while order is not important in a combination.
if this was a combination instead of a permutation, then your possible sets would be:
HELL
HLLE
LLHE
for example:
HELL AND EHLL contain the same letters, but in a dirrerent order.
as a permutation, they are considered members of separate sets.
as a combination, they are considered members of the same set.

RELATED QUESTIONS

(1)in how many ways can 4 boys and 3 girls be arrange in a line if the 3 girls are to (answered by KMST,ikleyn)
Find the number of ways of permitting the letters of the word HELL, such that: a) The... (answered by ikleyn)
in how many ways can the letter of the word "HELL" be permuted, if the two 2LLs must... (answered by ikleyn,math_helper)
How many ways can you arrange the letters of the word EDUCATION, such that the vowels are (answered by math_tutor2020)
1.in how many ways can the letters of the word WORLD be arranged such that O and R may... (answered by edjones)
In how many different ways can the letters of the word KNOWLEDGE be arranged in such a... (answered by Edwin McCravy)
In how many different ways can the letters of the word BADMINTON be arranged such that... (answered by greenestamps)
in how many different ways can the letters of word "MATHEMATICS" be arranged so that... (answered by Edwin McCravy)
How many ways the word BALLOON can be arranged, where O's will be always... (answered by oscargut)