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There are 10 letter in the word.
They all are UNIQUE, except one letter " S ", which has multiplicity of 2.
Therefore, the number of all distinguishable arrangements of the letters is = = 1814400. ANSWER
2! in the formula serves to account for repeation letter " E ".
Solved.
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To see other similar solved problems, look into the lesson
- Arranging elements of sets containing indistinguishable elements
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
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Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
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