SOLUTION: There are six seat in a railway carriage. In how many different ways can 4 people occupy them? My calculation : 6!x2! and I think the answer is wrong

Algebra ->  Permutations -> SOLUTION: There are six seat in a railway carriage. In how many different ways can 4 people occupy them? My calculation : 6!x2! and I think the answer is wrong       Log On


   



Question 1157603: There are six seat in a railway carriage. In how many different ways can 4 people occupy them?
My calculation : 6!x2!
and I think the answer is wrong

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.

Your answer is wrong.

The correct answer is  6*5*4*3 = 360 ways,  the product of  4 consecutive integer numbers,
starting from  6  in descending order.         ANSWER


The mantra is standard for all such problems:

    We can place item 1 in any of 6 positions;

                 item 2 in any of 5 remaining positions;

                 item 3 in any of 4 remaining positions;

                 item 4 in any of 3 remaining positions.

Solved, answered and explained.

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This problem is about PERMUTATIONS.

On Permutations,  see introductory lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations

    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.