.
In all, there are 22 + 28 = 50 students and 2 different positions.
Anyone of students can be selected for the first position, giving 50 options.
Anyone of remaining 49 students can be selected for the second position, giving 49 options.
The total number of ways is 50*49 = 2450. ANSWER
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Notice, that in this problem the goal is NOT to select a pair, without looking on the order in the pair.
The goal is to select persons to certain positions, which makes the order essential.
So we use permutations --- not combinations.
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On Combinations and Permutations, see the lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Problems on Permutations
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site. // I listed here the "introductory" lessons only . . .
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.