SOLUTION: A carton contains 15 transistors of which 5 are defective. If a random sample of 6 transistors are drawn from the carton (without replacement) determine the probability of 2 defect

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Question 1149524: A carton contains 15 transistors of which 5 are defective. If a random sample of 6 transistors are drawn from the carton (without replacement) determine the probability of 2 defective valves in the sample.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


solution deleted -- did not read the problem correctly
Answer by ikleyn(52779)   (Show Source): You can put this solution on YOUR website!
.
A carton contains 15 transistors of which 5 are defective. If a random sample of 6 transistors are drawn from the carton
(without replacement). Determine the probability of 2 defective transistors in the sample.
~~~~~~~~~~~~~~~ 


The sample space in this case is the set of all groups of 6 transistors that can be selected from 15 transistors.


The number of such groups is the number of combinations of 15 items taken 6 at a time

     =  = 5005.



The favorable set is the set of all groups of 6 transistors that contain 2 defective and 4 valid transistors.


The number of such groups is


    . = . = 10*210 = 2100.


The probability under the problem's question is


    P =  = 0.4196 = 41.96%  (approximately).    ANSWER

Solved.


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