.
The number of distinguishable arrangements is = 907200.
Here 10 is the number of letters in the given word; 2! is to account for 2 identical letters "o"
and the other 2! is to account for 2 identical letters "p".
The "magic" word is "population", I think.
The probability to get this arrangement among all other distinguishable arrangements is .
The probability to have the relevant permutation among all possible permutations is the same value .
Regarding the other problem, there is a rule in this forum, that each post can carry ONE and ONLY ONE PROBLEM.
---------------
To see other solved problems on distinguishable arrangements/permutations, look into the lesson
- Arranging elements of sets containing indistinguishable elements
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.