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Let the three persons be A, B and C.
Case 1. The person A receives nothing.
Then the person B receives some subset of 5 different objects, and the person C receives the rest
(receives the complement to the set that B receives).
So, there are as many different ways to distribute in this case, as many there are different subsets
in the set of 5 elements.
The answer to the last question is well known: there are = 32 different subsets of the set
of 5 distinguishable objects.
So, the answer to the case 1 is = 32 ways.
Now, cases when the person B or C receives nothing are absolutely symmetric to Case 1.
So, the answer to the problem's question is = 3*32 = 96.
Solved.