.
There are nine female board members and twenty-one male board members.
(a) How many ways are there to make a committee of twelve board members if exactly two must be female?
(b) Determine the probability of selecting a committee of twelve board members where exactly two of the members were female.
Write your answer as a decimal, rounded to the nearest thousandth.
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(a) You can select 2 females of 9 females by = = 36 ways.
You can select 12-2 = 10 males of 21 males by = = ways = 352716 ways.
The answer to question (a) is the product of these numbers
. = 36 * 352716 = 12697776 ways.
(b) To answer question (b), you need to divide the answer to question (a) by the number of all combinations
of 21 items taken 12 at a time :
P = = .
I leave it to you to calculate the number and to complete this assignment. It is just pure mechanical work.
Happy calculations !
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On Combinations, see the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.