SOLUTION: if all permutations of the letters of the word AGAIN are arranged as in dictionary,then the 50th word is:

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Question 1135367: if all permutations of the letters of the word AGAIN are arranged as in dictionary,then the 50th word is:
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52779)   (Show Source): You can put this solution on YOUR website!
.

For solving such problems, there is beautiful Internet site

    https://www.dcode.fr  

which has a section devoted to permutations  https://www.dcode.fr/permutations-generator.


It asked me what items I want to permute, and I pointed 5 letters A, G, A, I and N.


Then it asked me, if I want to have only DISTINGUISHABLE words as the output, and I answered "Yes".


In response, it generated 60 =   words placing them in column.


This output can be ordered in ascending or descending order - I selected "descending", exactly as in a dictionary 
(it is also called lexicographic order).


From the list, I copied the 50-th line.


It is the word  "NAAIG" ,  which is your    ANSWER.

Probably, I could solve the problem without the help from this solver,
but in this case I decided to save my brain and my time.


Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Given the usually excellent responses from tutor @ikleyn, I am CERTAIN she could have solved the problem without using the web site.

Given that the number of letters is relatively small, I would prefer to get the mental exercise....

(1) A _ _ _ _ : the remaining letters are AGIN; the number of permutations is 4! = 24

(2) G _ _ _ _ : the remaining letters are AAIN; the number of permutations is 4!/2! = 12; total number of permutations to this point = 24+12 = 36

(3) I _ _ _ _ : the remaining letters are AAGN; the number of permutations is 4!/2! = 12; total number of permutations to this point = 36+12 = 48

The 49th word is the first word that begins with N: NAAGI

The 50th word is the second word the begins with N: NAAIG
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