SOLUTION: Roy must elect 3 courses from among 3 courses in group I and 6 courses in group II. If he must take at least 1 of his 3 electives from each group, how many choices does he have?(Hi
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Question 1131671: Roy must elect 3 courses from among 3 courses in group I and 6 courses in group II. If he must take at least 1 of his 3 electives from each group, how many choices does he have?(Hint: First find how many choices he has if he elects only 1 course from group I. Then find how many choices he has if he elects 2 courses from group I. Since he must do one or the other of these, the final answer is the sum of the two answers.)
I think the answer is 36
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
A straightforward application of "n choose r" and basic rules of counting.
Choose 1 of the 3 courses in group I AND 2 of the 6 courses in group II, OR choose 2 of the 3 courses in group I AND 1 of the 6 courses in group II:
If you aren't familiar with C(n,r) ("n choose r") then search the internet and learn about it. It is basic to many types of problems similar to this one.
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Regarding combinations and , you don't need to go far and to search in the Internet. See the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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