.
If neglect the restriction, then the number of ways is = = = 1001.
Of this number of ways, some groups are prohibited. They are those that include Marge and Joel, complemented by 2 other,
arbitrary chosen persons of remaining (8+6)-2 = 12 persons.
So, the number of the prohibited groups is = = 66.
Then the answer to the problem's question is this difference
1001 - 66 = 935.
Solved.
-------------------
On Combinations, see the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.