SOLUTION: A catering service offers
6 appetizers,
4 main courses, and
8 desserts. A customer is to select
2 appetizers,
3 main courses, and
3 desserts for a banquet. In how many ways c
Algebra.Com
Question 1120544: A catering service offers
6 appetizers,
4 main courses, and
8 desserts. A customer is to select
2 appetizers,
3 main courses, and
3 desserts for a banquet. In how many ways can this be done?
Found 2 solutions by Shin123, greenestamps:
Answer by Shin123(626) (Show Source): You can put this solution on YOUR website!
There are 6C2+4C3+8C3 ways. There are 15+4+56=75 ways.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
The answer is the PRODUCT of the numbers of ways to select the appetizers, main courses, and desserts -- not the SUM.
Correct answer: (6C2)*(4C3)*(8C3) = 15*4*56 = 3360
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