Case 1: 3 women and 1 man Choose the 3 women 5C3 ways. Choose the 1 man 6C1 ways. That's (5C3)(6C1) = (10)(6) = 60 ways for case 1. Case 2: 4 women and no men Choose the 4 women 5C4 ways. That's 5C4 = 5 ways for case 2. ------------------------------------ Answer: 60+5 = 65 ways. Edwin