SOLUTION: In how many ways can a party of 6 children be chosen from a group of 10 children if if:(i) any child may be selected? (ii) the oldest child must not be selected? (iii) the youngest

Question 1115716: In how many ways can a party of 6 children be chosen from a group of 10 children if if:(i) any child may be selected? (ii) the oldest child must not be selected? (iii) the youngest child must be selected? (iv) the youngest and the oldest must both be selected
Found 2 solutions by MusabShakeel, ikleyn:
Answer by MusabShakeel(1)   (Show Source): You can put this solution on YOUR website!
Hi,
Your question is belong to permutation.Use the combination method.Answers:
(1)210 ways (2)84 ways
(3)84 ways
(4)210 ways.If answers were wrong I apologise for that.
Thanks!
Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.

(i) = = 210 (= the number of combinations of 10 items taken 6 at a time). (ii) = = 84. (iii) = = 126. (iv) = = 70.

----------------
On Combinations, see the lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.

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