SOLUTION: In how many ways can a team of 20 hockey
players be accommodated in 10 two-person
hotel rooms? Assume that the order of
assigning the rooms does not matter.
Algebra.Com
Question 1110654: In how many ways can a team of 20 hockey
players be accommodated in 10 two-person
hotel rooms? Assume that the order of
assigning the rooms does not matter.
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In how many ways can a team of 20 hockey
players be accommodated in 10 two-person
hotel rooms? Assume that the order of
assigning the rooms does not matter.
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Ans: 20C2 = (20*19)/(1*2) = 10*19 = 190 ways
---------------
Cheers,
Stan H.
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Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
.
This mathematical conception is called "Combinations".
On Combinations, see the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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