SOLUTION: A bus starts with 6 people and stops at 10 different stops, how many different ways can the 6 people depart if any passenger can depart at any bus stop

Question 1108155: A bus starts with 6 people and stops at 10 different stops, how many different ways can the 6 people depart if any passenger can depart at any bus stop

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

1-st person can go out at any of 10 bus stops - 10 opportunities.
2-nd person can go out at any of 10 bus stops - 10 independent opportunities.
3-rd person can go out at any of 10 bus stops - 10 independent opportunities.
4-th person can go out at any of 10 bus stops - 10 independent opportunities.
5-th person can go out at any of 10 bus stops - 10 independent opportunities.
6-th person can go out at any of 10 bus stops - 10 independent opportunities.


In all, there are   different ways.


Same number of ways as how many 6-letter words do exist comprising of 10 given letters (symbols) of the alphabet, if letters repetition is allowed.

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I just solved it at least two times in this forum.

See the lesson
- Combinatoric problems for entities other than permutations and combinations
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Combinatorics: Combinations and permutations".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.

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