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in how many ways can five couples be seated in a row if
a. there are no restrictions? 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 ways.
b. each couple must be seated together?
= 120*32 = 3840 ways (120 permutations for 5 objects, each of which can be in one
of the two states: (h,w) or (w,h), where "h" stands for husband and "w" stands for wife.
c. each husband must be seated to the left of his wife? 5! = 5*4*3*2*1 = 120 ways.