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What I see in the first line, this phrase
"how many unique arrangments (different people on left and right) how many arrangments are possible when seating 6?"
is not a formulation of a math problem. It is rather somebody's fantasy.
The correct formulation is THIS:
how many different arrangements are possible for 6 people seating in row ?
And then the answer is: 6! = 1*2*3*4*5*6 = 720.
Any of 6 in the most left position;
Any of remaining 5 in the next position;
Any of remaining 4 in the next position;
Any of remaining 3 in the next position;
Any of remaining 2 in the next position;
And for the last position there is only one possibility.
In all, there are 720 arrangements.
Solved.
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Next time, when you need HELP in solving your assignment, write it word-in-word as it is formulated in your assignment, PLEASE.
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On Permutations, see the lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Problems on Permutations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".