SOLUTION: how many unique arrangments (different people on left and right) how many arrangments are possible when seating 6? i have tried multiplying and permutations and drawing out the an

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Question 1089981: how many unique arrangments (different people on left and right) how many arrangments are possible when seating 6?
i have tried multiplying and permutations and drawing out the answer but because 5 has 24 different solutions i dont want to draw that much. what is the easiest way to solve this?

Answer by ikleyn(53937)   (Show Source): You can put this solution on YOUR website!
.
What I see in the first line, this phrase

    "how many unique arrangments (different people on left and right) how many arrangments are possible when seating 6?"


is not a formulation of a math problem.  It is rather somebody's fantasy.


The correct formulation is THIS:

    how many different arrangements are possible for 6 people seating in row ?


And then the answer is:  6! = 1*2*3*4*5*6 = 720.


Any of           6 in the most left position;
Any of remaining 5 in the next position;
Any of remaining 4 in the next position;
Any of remaining 3 in the next position;
Any of remaining 2 in the next position;
And for the last position there is only one possibility.


In all, there are 720 arrangements.

Solved.

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Next time, when you need HELP in solving your assignment, write it word-in-word as it is formulated in your assignment, PLEASE.
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On Permutations,  see the lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".


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