SOLUTION: In a box there are 3 orange balls,4 blue balls and 5 brown balls.what is the probability of drawing three balls​ simultaneously and 1)they are of the same color? 2)they are

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Question 1088356: In a box there are 3 orange balls,4 blue balls and 5 brown balls.what is the probability of drawing three balls​ simultaneously and
1)they are of the same color?
2)they are of 3 different colors?

Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
In a box there are 3 orange balls,4 blue balls and 5 brown balls.what is the probability of drawing three balls​ simultaneously and
1) they are of the same color?
2) they are of 3 different colors?
~~~~~~~~~~~~~~~~~

1.  The total number of balls is 3 + 4 + 5 = 12.

    Hence, there are    of possible outputs when you draw three balls simultaneously.

    So, your space of events counts   = 220 elements (events, outputs).

    The number of lucky events is   +  +  =  +  +  = 3+4+10 = 15.


    The probability to draw 3 balls of the same color is  = .



2.  In how many ways can you get the output of 3 different colors ?

    In 3*4*5 = 60 ways.

    Indeed, you may have any one of 3 orange balls, any one of 4 blue balls and any one of 5 brown balls- in all, 60 outputs.

    Therefore, the probability to draw 3 balls of different colors is  = .

Solved.


On Combinations,  see the lessons
    - Introduction to Combinations
    - PROOF of the formula on the number of Combinations
    - Problems on Combinations
    - OVERVIEW of lessons on Permutations and Combinations
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations".



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