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In a box there are 3 orange balls,4 blue balls and 5 brown balls.what is the probability of drawing three balls simultaneously and
1) they are of the same color?
2) they are of 3 different colors?
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1. The total number of balls is 3 + 4 + 5 = 12.
Hence, there are of possible outputs when you draw three balls simultaneously.
So, your space of events counts = 220 elements (events, outputs).
The number of lucky events is + + = + + = 3+4+10 = 15.
The probability to draw 3 balls of the same color is = .
2. In how many ways can you get the output of 3 different colors ?
In 3*4*5 = 60 ways.
Indeed, you may have any one of 3 orange balls, any one of 4 blue balls and any one of 5 brown balls- in all, 60 outputs.
Therefore, the probability to draw 3 balls of different colors is = .
Solved.
On Combinations, see the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".