SOLUTION: A RANDOM SAMPLE OF 400 MEMBERS OF LABOR FORCE IN A FIVE STATE REGION SHOWED THAT 32 WERE UNEMPLOYED. CONSTRUCT THE 95% CONFIDENCE INTERVAL FOR THE PROPORTION UNEMPLOYED IN THE REGI

Question 1085207: A RANDOM SAMPLE OF 400 MEMBERS OF LABOR FORCE IN A FIVE STATE REGION SHOWED THAT 32 WERE UNEMPLOYED. CONSTRUCT THE 95% CONFIDENCE INTERVAL FOR THE PROPORTION UNEMPLOYED IN THE REGION.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The interval width is z(0.975)*sqrt (0.08*0.92)/400; sqrt term=0.01356.
The 0.975 is the z-value with 0.025 on each end or 95%. The sqrt is of p*(1-p)/n, and p is 32/400=0.08, the point estimate.
0.0266 is the interval width.
That is above and below the point estimate
(0.0534, 0.1066) is 95% CI

RELATED QUESTIONS
Q1)A NORMAL POPULATION HAS STANDARD DEVIATION OF 10. A RANDOM SAMPLE OF SIZE 25 HAS A... (answered by ikleyn)

govt. data shows that 10% of males under age 25 are unemployed. A random sample is... (answered by stanbon)

Data from the Bureau of Labor Statistics indicates that in a certain�month,... (answered by Boreal)

In 2014, a country's civilian labor force consisted of 271,011,000 persons. Of... (answered by ikleyn)

An employment counselor found that in a sample of 100 unemployed workers, 65% were not... (answered by Boreal)

Labor Force Couples The percentage of couples where both parties are in the labor force... (answered by Boreal)

1.Suppose a population hold the ages of five family members,as follows: 1,13,32,34, and... (answered by CPhill)

3. A market research consultant hired by Coke Classic Company is interested in estimating (answered by CPhill)