SOLUTION: How many different committees of 5 people can be chosen from 10 people?

Question 1081515: How many different committees of 5 people can be chosen from 10 people?
Found 3 solutions by Edwin McCravy, josmiceli, jim_thompson5910:
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
10 people, choose 5 = 10C5 = 252
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
C( 10,5 ) =
C( 10,5 ) =
C( 10,5 ) =
C( 10,5 ) =
252 different committees
check the math

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Use the combination formula (nCr) to get...

n C r = (n!)/(r!(n-r)!)

10 C 5 = (10!)/(5!*(10-5)!)

10 C 5 = (10!)/(5!*5!)

10 C 5 = (10*9*8*7*6*5*4*3*2*1)/((5*4*3*2*1)*(5*4*3*2*1))

10 C 5 = (3628800)/((120)*(120))

10 C 5 = (3628800)/(14400)

10 C 5 = 252

Answer: 252
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