We line up the 5 girls in 5!=120 ways. _G_G_G_G_G_ Next we will insert the boys among the girls. There are 6 insertion places to choose for the boys to be inserted, indicated above by "_"'s. We choose two boys to sit together left to right in 4*3 = 12 ways. We choose an insertion place for that pair of boys any of 6 ways. We choose a different insertion place for the older of the two remaining boys any of 5 ways. We choose another different insertion place for the one remaining boy any of 4 ways. Answer: (120)(12)(6)(5)(4) = 172800 ways. Edwin