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In how many ways can 2 men, 4 women, 3 boys and 3 girls be selected from 6 men, 8 women, 4 boys and 5 girls if no restrictions are imposed
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= = 3*5 = 15 ways for men.
= = 7*2*5 = 70 ways for women.
= 4 ways for boys.
= = 5*2 = 10 ways for girls.
In total, 15*70*4*10 ways.
This problem is about combinations.
On combinations, see the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".