SOLUTION: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?

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Question 1049797: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?
Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
4! is the number of permutations of four objects.

In your case the objects are "classes".

On permutations, see the lessons
    - Introduction to Permutations
    - PROOF of the formula on the number of Permutations
    - Problems on Permutations
in this site.


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