SOLUTION: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?
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Question 1049797: Two freshmen, 2 sophomores, 2 juniors, and 3 seniors are on a panel. In how many ways can the panelists be seated if each class must sit together?
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
4! is the number of permutations of four objects.
In your case the objects are "classes".
On permutations, see the lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Problems on Permutations
in this site.
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