The number of 5-person committees that include Zubeda, we choose Zubeda in exactly 1C1 = 1 way, and we choose the other 4 members from the other 8 people in 8C4 ways. That's 1 times 8C4 or 8C4. The number of 5-person committees (whether or not they include or exclude Zubeda) is 9C5 Answer: Edwin