We can choose the pair of positions for A and B to be in in 5C2 = 10 ways. In each of those 10 ways we can always put Ann left of Bob. To illustrate, we could have Ann and Bob in any of the following 5C2 = 10 ways, with Ann always left of Bob, but not necessarily beside him. 1. A B _ _ _ 2. A _ B _ _ 3. A _ _ B _ 4. A _ _ _ B 5. _ A B _ _ 6. _ A _ B _ 7. _ A _ _ B 8. _ _ A B _ 9. _ _ A _ B 10. _ _ _ A B Then for each of those 5C2 = 10 ways to place Ann and Bob, the remaining 3 people can be arranged in the 3 blanks in 3! or 6 ways: Answer: (5C2)(3!) = (10)(6) = 60 ways. Edwin