SOLUTION: Approximately 14% of people are left-handed. If two people are selected at random, what is the probability of the following events? A. P(Both are right-handed) = B. P(Bot

Question 1032431: Approximately 14% of people are left-handed. If two people are selected at random, what is the probability of the following events?
A. P(Both are right-handed) =
B. P(Both are left-handed) =
C. P(One is right-handed and the other is left-handed) =
D. P(At least one is right-handed) =

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Approximately 14% of people are left-handed. If two people are selected at random, what is the probability of the following events?
A. P(Both are right-handed) = 0.86^2
B. P(Both are left-handed) = 0.14^2
C. P(One is right-handed and the other is left-handed) = 1-[0.86^2+0.14^2]
D. P(At least one is right-handed) = 1 - 0.14^2
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Cheers,
Stan H.
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