SOLUTION: A set of 101 hypothetical CWU students were surveyed about whether they lived on or off campus and how much ice cream they ate per week. The results are shown below:
Ice Cream
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Question 1031844: A set of 101 hypothetical CWU students were surveyed about whether they lived on or off campus and how much ice cream they ate per week. The results are shown below:
Ice Cream On-campus Off-campus
At most two scoops 23 27
Three to five scoops 21 16
More than five scoops 5 9
(a) What is the probability that a randomly chosen student lives on campus?
(b) If a person eats at most two scoops of ice cream per week, what is the probability that they live on campus?
(c) If a person lives on campus, what is the probability that they eat at most two scoops of ice cream per week?
(d) Are the events "lives on campus" and "eats at most two scoops of ice cream per week" independent? Your answer should be "Y" or "N".
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A set of 101 hypothetical CWU students were surveyed about whether they lived on or off campus and how much ice cream they ate per week. The results are shown below:
Ice Cream......... On-campus Off-campus...Totals
At most two scoops... 23........ 27.........50
Three to five scoops. 21........ 16.........37
More than five scoops. 5......... 9.........14
Totals................49.........52.........101
(a) What is the probability that a randomly chosen student lives on campus?
-----49/101
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(b) If a person eats at most two scoops of ice cream per week, what is the probability that they live on campus?
-----23/50
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(c) If a person lives on campus, what is the probability that they eat at most two scoops of ice cream per week?
-----23/49
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(d) Are the events "lives on campus" and "eats at most two scoops of ice cream per week" independent? Your answer should be "Y" or "N".
Question??: P(lives on camp)|eats >= 2 ) = P(lives on campus)*P(eats>=2)
(23/50) = (49/101)(50/101)
Answer:: No
Therefore the events are not independent?
Cheers,
Stan H.
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