SOLUTION: 2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party?

Question 1012876: 2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party?
Answer by ikleyn(52780) (Show Source): You can put this solution on YOUR website!
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2 parties each hold 6 people in how many ways can a party of 6 boys and 6 girls divide themselves so that they're equal number of boys and girls in each party?
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You can choose 3 boys of 6 for the first party by  =  = 20 ways.

You can choose 3 girls of 6 for the first party by  =  = 20 ways.

In total, you have 20*20 ways to choose 3 boys of 6 and 3 girls of 6 for the first party. 

The rest of the boys and the girls will participate in the 2nd party without choice.

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