SOLUTION: A box contains 15 transistors, 3 of which are defective. If 3 are selected at random. the probability that.
a. all are defective
b.none are defective
Algebra.Com
Question 1007465: A box contains 15 transistors, 3 of which are defective. If 3 are selected at random. the probability that.
a. all are defective
b.none are defective
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A box contains 15 transistors, 3 of which are defective. If 3 are selected at random. the probability that.
----
Assuming you don't put them back (w/o replacement):
a. all are defective
= (3/15)*(2/14)*(1/13)
= 1/455
=============
b. none are defective
= (12/15)*(11/14)*(10/13)
= 220/455
= 44/91
RELATED QUESTIONS
if a box contains 12 transistors, 3 of which are defective. If 3 are selected at random... (answered by stanbon)
A box contains 15 transistors, 3 of which are defective. If 3 are selected at... (answered by jim_thompson5910)
a box contains 25 transistors 6 of which are defective. if 6 are selected at random find... (answered by fractalier)
A box contains 11 transistors, 5 of which are defective. If 5 are selected at random find (answered by Fombitz)
A box contains 10 transistors , 4 of which were defective. If 4 are selected at random,... (answered by Fombitz)
A box contains 11 transistors , 5 of which were defective. If 5 are selected at random,... (answered by Fombitz)
A box contains 12 transistors , 5 of which were defective. If 5 are selected at random,... (answered by stanbon)
a box contains 30 transistors, 8 of which are defective. If 6 are selected at random ,... (answered by ewatrrr)
A box contains 21 transistors, 7 of which are defective. If 7 are selected at random,... (answered by stanbon)