SOLUTION: Could you please tell me what I did wrong with this problem? A horse race has 12 entries. Assuming there are no ties, what is the probability that the three horses owned by one

Question 1006539: Could you please tell me what I did wrong with this problem?
A horse race has 12 entries. Assuming there are no ties, what is the probability that the three horses owned by one person finish first, second, and third?
What I tried: 12!/(12-3)! = 12*11*10*9!/9!= 1320; P(1-owner of 3 horses place 1st, 2nd & 3rd) = 1/1320 = .00076

The textbook says the answer is .005.
Thank you.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
3 hoses out of the 12 must finish 1, 2, and 3
but their order doesn't matter. I get:

or about .005
or did I make it too simple?

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