SOLUTION: A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt

Question 1005536: A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt a full house consisting of three kings.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A full house consists of three of one kind and two of another kind. You are dealt a hand of five cards from a standard deck of 52 playing cards. Find the probability of being dealt a full house consisting of three kings.
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Pick 3 kings:: 4C3 = 4 ways
Pick 2 of another card type:: 12*4C2 = 12*6 = 72 ways
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P(full house) = (4*72)/52C5 = 288/2598960 = 0.0001108..
Cheers,
Stan H.
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