Questions on Algebra: Combinatorics and Permutations answered by real tutors!

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a) how many arrangements can be formed from all the letters in the word parallel?
8!/[2!*3!] = 3360
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b) In how many of these arrangements will the 3 l's be together?
Consider the 3 l's to be one letter.
Ans: 6!/2! = 360
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Cheers,
Stan H.

You can put this solution on YOUR website!
a)8!/(3!*2!) three Ls and 2 As
=(8*7*6*5*4*3!)/(3!*2!)
=3360
.
b)6!/2! Since all the Ls are together they behave as a single letter in a 6 letter word.
=6*5*4*3*2!/2!
=360
.
Ed