Questions on Algebra: Combinatorics and Permutations answered by real tutors!

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Question 159546: there are five students, they are A, B, C, D, and E. They are want to sit down on the chair. how many ways the five students can sit if A must beside B?: there are five students, they are A, B, C, D, and E. They are want to sit down on the chair. how many ways the five students can sit if A must beside B?
Answer by atique.ah(23) About Me  (Show Source):
You can put this solution on YOUR website!
There are 5 ways A can sit.
There is only 1 way that B can sit.
There are 3ways C can sit.
There are 2 ways that D can sit.
And last there is only 1 way left for E.
The total numbers of ways A B C D E can sit =5*1*3*2*1=30 ways.
Question 159546: there are five students, they are A, B, C, D, and E. They are want to sit down on the chair. how many ways the five students can sit if A must beside B?: there are five students, they are A, B, C, D, and E. They are want to sit down on the chair. how many ways the five students can sit if A must beside B?
Answer by serena B(1) About Me  (Show Source):
You can put this solution on YOUR website!
There are 5 students but 2 wants to sit to gether....so we count them as one
so there are 4 now
eg. CDE(AB)<< Ab is counted as one, however AB can sit 2 ways together either (BA) or (AB)
answer would be= 4! * 2!=48