# Lesson Percentage Word Problems (discount)

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### Source code of 'Percentage Word Problems (discount)'

This Lesson (Percentage Word Problems (discount)) was created by by mathick(4)  : View Source, Show

 A typical word problem involving percentages might look something like this: Ned got a 12% discount when he bought his new jacket. If the original price, before the discount, was \$50, how much was the discount? Word problems tend to be even wordier than this one. The solution process involves making the problem simpler and simpler, until it's a math problem with no words. Step 1. Identify what they're asking for, and call it x. x = amount of the discount. Step 2. Use the information given to write an equation that relates the quantities involved. 12% of 50 dollars = the amount of the discount (x). Step 3. Translate into Math:

(12/100) * 50 = x. Step 4. Solve for x:

6 = x. This means that Ned's 12% off amounted to a \$6 discount. A few examples of some word problems using this method are in the table below. You can try a sample problem if you'd like to practice and see if you're doing it correctly.
Problems:   A. The original price was \$160, and Ned got a 20% discount? How much was the discount? B. The original price was \$90, and Ned got a \$36 discount. How many percent off was the discount? C. Ned's discount was 20% off the original price, which meant a \$40 discount. What was the original price?
Write an equation:   A. What is 20% of 160? B. 36 is what percent of 90? C. 40 is 20% of what number?
Translate into math: is = “=” of = “*” What = “x” 5% = “5/100”, etc.    A.
What is
20%
of 160?
x = (20/100) * 160.

B.
36 is
what %
of 90?
36 = (x/100) * 90.

C.
40 is
20%
of what number?
40 = (20/100) * x.

Simplify & solve for x:
(This may involve solving a linear equation - click here to practice.)
A. x = (.2)*160, so x = 32 B. 36 = (.9)x, so x = 40 C. 40 = (.2)x, so x = 200