Let the amount of 60% solution to mix, be S
Then the amount of 30% solution to be mixed = 55 - S
The following antifreeze-solution equation is thus formed:
.6S + .3(55 - S) = .42(55)
.6S + 16.5 - .3S = 23.1
.6S - .3S = 23.1 - 16.5
.3S = 6.6
S, or amount of 60% solution to mix =, or gallons
Amount of 30% solution to be mixed = 55 - 22, orgallons