SOLUTION: The perimeter of a triangle is 210 meters. The longest side is 50 meters longer the shortest side. The remaining side is twice as long as the shortest side. Find the length of each

Question 959349: The perimeter of a triangle is 210 meters. The longest side is 50 meters longer the shortest side. The remaining side is twice as long as the shortest side. Find the length of each side.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
P=210
LET X BE THE SHORTEST SIDE.
LET X+50 BE THE SECOND SIDE.
LET 2X BE THE THIRD SIDE.
210=X+X+50+2X
210=4X+50
210-50=4X
160=4X
X=160/4
X=40 FOR THE SHORTEST SIDE.
40=50=90 FOR TH SECOND SIDE.
2*40=80 FOR THE THIRD SIDE.
PROOF:
210=40+80+80
210=210
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