SOLUTION: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account becaus

Question 858601: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 10956 dollars. How much did he invest at each rate? How much interest was earned on each account?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
10%--------------x
6%--------------2x
10%x+6% * 2x=10956
multiply by 100
10x+12x=1095600
22x= 1095600

x=1095600/22
x= 49,800--------------10%------------------$4980
2x= 99,600--------------6%-------------------$ 5976
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